2^x+1=1/32

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Solution for 2^x+1=1/32 equation: 



2^x+1=1/32

We move all terms to the left:

2^x+1-(1/32)=0

We add all the numbers together, and all the variables

2^x+1-(+1/32)=0

We get rid of parentheses

2^x+1-1/32=0

We multiply all the terms by the denominator


2^x*32-1+1*32=0

We add all the numbers together, and all the variables

2^x*32+31=0

Wy multiply elements

64x+31=0

We move all terms containing x to the left, all other terms to the right

64x=-31

x=-31/64

x=-31/64

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